Optimal. Leaf size=223 \[ -\frac{15 \sqrt{\frac{\pi }{2}} b^{5/2} e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}-\frac{15 \sqrt{\frac{\pi }{2}} b^{5/2} e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}+\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \]
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Rubi [A] time = 0.750858, antiderivative size = 223, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.643, Rules used = {5663, 5758, 5675, 5779, 3312, 3307, 2180, 2204, 2205} \[ -\frac{15 \sqrt{\frac{\pi }{2}} b^{5/2} e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}-\frac{15 \sqrt{\frac{\pi }{2}} b^{5/2} e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}+\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{c^2 x^2+1} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \]
Antiderivative was successfully verified.
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Rule 5663
Rule 5758
Rule 5675
Rule 5779
Rule 3312
Rule 3307
Rule 2180
Rule 2204
Rule 2205
Rubi steps
\begin{align*} \int x \left (a+b \sinh ^{-1}(c x)\right )^{5/2} \, dx &=\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{1}{4} (5 b c) \int \frac{x^2 \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{\sqrt{1+c^2 x^2}} \, dx\\ &=-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{1}{16} \left (15 b^2\right ) \int x \sqrt{a+b \sinh ^{-1}(c x)} \, dx+\frac{(5 b) \int \frac{\left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{\sqrt{1+c^2 x^2}} \, dx}{8 c}\\ &=\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{1}{64} \left (15 b^3 c\right ) \int \frac{x^2}{\sqrt{1+c^2 x^2} \sqrt{a+b \sinh ^{-1}(c x)}} \, dx\\ &=\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{\sinh ^2(x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{64 c^2}\\ &=\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}+\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \left (\frac{1}{2 \sqrt{a+b x}}-\frac{\cosh (2 x)}{2 \sqrt{a+b x}}\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{64 c^2}\\ &=\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{\cosh (2 x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{128 c^2}\\ &=\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{e^{-2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{256 c^2}-\frac{\left (15 b^3\right ) \operatorname{Subst}\left (\int \frac{e^{2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{256 c^2}\\ &=\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{\left (15 b^2\right ) \operatorname{Subst}\left (\int e^{\frac{2 a}{b}-\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{128 c^2}-\frac{\left (15 b^2\right ) \operatorname{Subst}\left (\int e^{-\frac{2 a}{b}+\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{128 c^2}\\ &=\frac{15 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}{64 c^2}+\frac{15}{32} b^2 x^2 \sqrt{a+b \sinh ^{-1}(c x)}-\frac{5 b x \sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}{8 c}+\frac{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}}{4 c^2}+\frac{1}{2} x^2 \left (a+b \sinh ^{-1}(c x)\right )^{5/2}-\frac{15 b^{5/2} e^{\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}-\frac{15 b^{5/2} e^{-\frac{2 a}{b}} \sqrt{\frac{\pi }{2}} \text{erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{256 c^2}\\ \end{align*}
Mathematica [A] time = 0.0720903, size = 115, normalized size = 0.52 \[ \frac{e^{-\frac{2 a}{b}} \left (b^3 e^{\frac{4 a}{b}} \sqrt{\frac{a}{b}+\sinh ^{-1}(c x)} \text{Gamma}\left (\frac{7}{2},\frac{2 \left (a+b \sinh ^{-1}(c x)\right )}{b}\right )-b^3 \sqrt{-\frac{a+b \sinh ^{-1}(c x)}{b}} \text{Gamma}\left (\frac{7}{2},-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )}{b}\right )\right )}{32 \sqrt{2} c^2 \sqrt{a+b \sinh ^{-1}(c x)}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.057, size = 0, normalized size = 0. \begin{align*} \int x \left ( a+b{\it Arcsinh} \left ( cx \right ) \right ) ^{{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}} x\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}} x\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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